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(1).x甲=15(10+8+9+8+10)=9;.x乙=15(9+8+9+10+9)=9;
S2甲=15[(10-9)2+(8-9)2+(9-9)2+(8-9)2+(10-9)2]=0.8;
S2乙=15[(9-9)2+(8-9)2+(9-9)2+(10-9)2+(9-9)2]=0.4;
(2)∵S2甲>S2乙,
∴乙的稳定性好,派乙去.
故答案为0.8,0.4.